512t^2-200=0

Solution for 512t^2-200=0 equation:

512t^2-200=0

a = 512; b = 0; c = -200;
Δ = b2-4ac
Δ = 02-4·512·(-200)
Δ = 409600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{409600}=640$
$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-640}{2*512}=\frac{-640}{1024}
=-5/8
$
$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+640}{2*512}=\frac{640}{1024}
=5/8
$